The given line segment has a midpoint at (3, 1).
What is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment?
y = x
y = x – 2
y = 3x
y = 3x − 8
Answers
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Given : The given line segment has a midpoint at (3, 1).
line segment has end points ( 2 , 4) and ( 4, -2 )
To Find : equation, in slope-intercept form, of the perpendicular bisector of the given line segment?
Solution:
line segment has end points ( 2 , 4) and ( 4, -2 )
Slope = ( - 2 - 4)/(4 - 2) = - 6/2 = - 3
Slope of perpendicular line = -1/-3 = 1/3
Equation of perpendicular bisector as it passes through ( 3 , 1)
y - 1 = (1/3) (x - 3)
=> 3y - 3 = x - 3
=> y = x/3
y = x/3 is the Equation of perpendicular bisector
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