A charged particle is fired at an angle to a uniform magnetic field directed along the X-axis during it's motion along helical path if the pitch of helix is equal to maximium distance of the particle from the X-axis, then
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Explanation:
Pitch =(2π
ϕB
m
)vcosθ
Also mvsinθ=QBR
For motion perpendicular to the magnetic field
Or,r=
QB
mv
sinθ
Maximum distance of the particle from the x-axis = 2r
∴[2π
QB
m
]vcosθ=2
QB
mv
sinθ
or, tanθ=π
Hence (A) & (D) are correct.
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