Question

A charged particle is moving in a uniform magnetic field in a circular path with a radius R with energy of the particle is doubled then the new radius will be

Answer 1

HEY DEAR .

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r=mvqB=2mE√qBr=mvqB=2mEqB

⇒r∝E√⇒r∝E

r′r=2EE−−−√=2√r


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