A charged particle is moving in a uniform magnetic field in a circular path with a radius R with energy of the particle is doubled then the new radius will be
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HEY DEAR .
__________________________
r=mvqB=2mE√qBr=mvqB=2mEqB
⇒r∝E√⇒r∝E
r′r=2EE−−−√=2√r
HOPE , IT HELPS .
FOLLOW ME . ✌
__________________________
r=mvqB=2mE√qBr=mvqB=2mEqB
⇒r∝E√⇒r∝E
r′r=2EE−−−√=2√r
HOPE , IT HELPS .
FOLLOW ME . ✌
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