Physics, asked by rajusurjit7023, 1 year ago

A charged particle of 2nc moving in a magnetic field b, perpendicular to field with a velocity v=10i m/s experiences a magnetic force f=2*10^-5(-j)n. Find direction and magbitude of the magnetic field

Answers

Answered by Anonymous
0
force = q( v× b) through this u can find direction and magnitude
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