Question

A charged particle of mass 2 mg remains freely in air in an electric field of strength 4 N/ C directed upward . Calculate the charge and determine its nature ( g= 10 m / s2

Answer 1

hence, charge on particle is 5mC and nature of it is positive.

An electric field of strength 4N/C is acting on charged particle which is directed upward direction.

weight of charged particle is acting downward so, to balance weight of it electrostatic force must be acted upward. this is possible only when charge is positive in nature.

at equilibrium,

weight of charged particle = electrostatic force.

⇒mg = Eq

where m is mass of charge particle, g is acceleration due to gravity, E is electric field strength and q is charge on particle.

so, q = mg/E

= (2mg × 10m/s²)/(4N/C)

= (2 × 10^-3 kg × 10m/s²)/(4N/C)

= 5 × 10^-3 C

= 5mC

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Answer 2

$\huge\bold\purple{Answer:-}$

mass = 2×10^-6kg

E= 4 newton per coulomb

F =qe...eq(1)

and. F =mg....eq(2)

comparing both

mg=qe

then

q=mg/E

substitute the values and answer will be 4.9×10^-6 coulomb

hope it helps