A cheetah can accelerate from rest to at at the rate of 4 meters per second square . What will be the velocity attained by it in 10 seconds . How far will it travel in this duration
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Assuming that the cheetah is moving along a straight line
here Acceleration(a)=4m/sec
time (t)=10 seconds
let 'v' be the final velocity and 'u' be the initial velocity
Here u=0 as cheetah was initially at rest
by the first kinematic equation we get
v=u+at
v=0+4*10
v=40m/sec
therefore velocity is 40 m/sec in same direction. and
By third kinematic equation we get
s=ut + 1/2 at^2
here s is distance
s=0+1/2*4*(10)^2
s=200 m
therefore distance traveled is 200 m
Hope this helped u
:-)
here Acceleration(a)=4m/sec
time (t)=10 seconds
let 'v' be the final velocity and 'u' be the initial velocity
Here u=0 as cheetah was initially at rest
by the first kinematic equation we get
v=u+at
v=0+4*10
v=40m/sec
therefore velocity is 40 m/sec in same direction. and
By third kinematic equation we get
s=ut + 1/2 at^2
here s is distance
s=0+1/2*4*(10)^2
s=200 m
therefore distance traveled is 200 m
Hope this helped u
:-)
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19
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