A cheetah can accelerate from the rest at the rate of 4 m/s.how far will it travel?
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Answer:
The Distance will be 2 m.
Explanation:
Acceleration (a) = 4 m/s²
Final Velocity (v) = 4 m/s
Initial Velocity (u) = 0 m/s
Let the Distance be S.
According to formula,
v² = u² + 2aS
= 4² = 0² + 2*4*S
= 16 = 8S
= 2 m = S
Hope this helps.
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