Question

a cheetah can accelerates from rest of 4 m per second. (1) what will be the velocity attained by it (2) how far it will travel in this duration.

Answer 1

1- initial velocity (u) = 0 , acceleration (a) = 4m/s(raised to 2)
v = u + at
   = 0 + 4 * 10
v = 40m/s
v2 = u2 + 2as
v2 = 0square + 2as
v2 = 2as
s   = v2/2a
s = 40 * 40/2*4
s = 1600/8 = 200 m