A polygon of n side n(n-3)÷2diagonals.how many sides has a polygon with 54 diagonals
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n(n-3)/2=54
n^2-3n=108
n^2-3n-108=0
n^2-12n+9n-108=0
n(n-12)+9(n-12)=0
therefore
n=12 or n=-9
but actually side will not be in negative therefore
side will be 12.
if my answer is helpful for you then please mark as brain liest
n^2-3n=108
n^2-3n-108=0
n^2-12n+9n-108=0
n(n-12)+9(n-12)=0
therefore
n=12 or n=-9
but actually side will not be in negative therefore
side will be 12.
if my answer is helpful for you then please mark as brain liest
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