A cheetah is at rest. It accelerates at 4 m s−2 for 20 seconds. Calculate distance travelled after 20 second.
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GIVEN
A cheetah is at rest. It accelerates at 4 m s−2 for 20 seconds.
TO FIND
Calculate distance travelled after 20 second.
SOLUTION
- Initial velocity (u) = 0
- Acceleration (a) = 4m/s²
- Time (t) = 20 s
- Distance (s) = ?
According to second equation of motion
→ s = ut + ½ at²
→ s = 0*20 + ½ × 4 × (20)²
→ s = 0 + 2 × 400
→ s = 800 m
Hence, distance travelled after 20s is. 800m
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