Question

A cheetah starts from rest. And acceleratesat2m/s^2 for10 seconds. Calculate: the final velocity. The distance travelled.

Answer 1

Assuming that the cheetah is moving along a straight line
here Acceleration(a)=2
time (t)=10 sec
here by 1st kinematic equation we get
v=u+at
v=0+4*10  (as the cheetah was initially at rest therefore u=0)
v=40 m/sec
therefore final velocity 40 m/sec in the same direction
distance travelled is
s=ut+1/2at^2
s=0+1/2*2*10^2
s=1/2*2*100
s=100m
Therefore distance travelled is 100m

Answer 2

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