Question

A chemist had one solution containing 50% acid and second containing 25% acid how much of each should be used to make 10liters of 40%acid solution

Answer 1

Answer:
    Total Volume of 40% solution = 10 litres
  Let volume of 50% solution = x
       therefore , volume of 25% solution = total volume of solution  - volume of 50% solution
                                             =10 - x
 
     we know that,
        x*50+(10-x)*25 =40*10
       (50x +250 -25x) = 400
        25x +250 = 400
        25x =400 - 250
      or 25x =150
     or x =150/25
    or x =6
   there litres of 50% litre solution in mixture = 6 
    hence litres of 25% solution in mixture = 10 - x =10 -6 = 4

Therefore , Chemist will add 6 litres of 50% solution and 4 litres of 25% solution.

Hope this helps you.
Thank you.
 

Answer 2

plz refer to this attachment