Question

A chemist needs 1.5 M HCl for a reaction. The solution available is 6 M of HCl. What is
volume of 6 M HCl to be diluted to obtain 5 L of 1.5 M HCl?​

Answer 1

Given:

Molarity of HCl required, M1 = 1.5 M

Molarity of HCl available, M2 = 6 M

Volume of HCl required, V1 = 5 L

To Find:

Volume of 6 M HCl solution to be diluted, i.e., V2.

Calculation:

Using molarity equation, we get:

M1 × V1 = M2 × V2

⇒ V2 = M1 × V1/M2

⇒ V2 = 1.5 × 5 / 6

⇒ V2 = 1.25 L

- So, 1.25 L of 6 M HCl is required to be diluted to obtain 5 L of 1.5 M HCl.