Question

dt 3x² dt 3 (20)2 (0.3) 4000 cm/ min
EXERCISE-1
PART-B
1. A stone projected vertically upwards is at a height S feet after 1 sec where S=80t - 16t. Find
(i) Its initial velocity
(ii) Its velocity at t = 1 sec
(iii) Time when it is at rest
(iv) the greatest height above the ground
April 2015 (Common) ; 2013 [DME, CME) ; 2008|DME) ; Oct. 2013 Common
2. A particle is moving along a straight line according to the law S = 213 - 3t2 - 15t + 18
(t is in seconds). Find its velocity when its acceleration is zero.
3. The distance S (in metres) and time t (in seconds) of a particle moving along a straight
line are connected by the relation S = 4t - 18t4 - 15. Find when the acceleration
becomes zero and determine the velocity at that time.
TEXTBOOK OF ENGINEERING MATHEMATICS​

Answer 1

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