Question

A chemist needs to mix 20l of a 40%acid solution with some 70% acid solution to obtain a mixture that is 50%acid How many liter of the 70% acid solution should be used ​

Answer 1

Ans:-

.70x+.40*20=.50(20+x)

.70x+8=10+.50x

.70x-.50x=10-8

.20x=2

x=2/.2

x=10 L of 70% acid is used.

Proof:

.70*10+.40*.2=.50(20=10)

7+8=.5*30

15=15

Answer 2

Answer:

70x+.40*20=.50(20+x)

.70x+8=10+.50x

.70x-.50x=10-8

.20x=2

x=2/.2

x=10 L of 70% acid is used.

Proof:

.70*10+.40*.2=.50(20=10)

7+8=.5*30

15=15

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