Question

A chemist needs to mix a 12% acid solution with a 32% acid solution to
obtain an 8‐liters mixture consisting of 20% acid. How many liters of each of
the acid solutions must be used?

Answer 1

Answer:

A chemist needs to mix a 12% acid solution with a 32% acid solution to obtain an 8-liters mixture consisting of 20% acid.

How many liters of each of the acid solutions must be used?

(Concentrations here are volume concentrations, measured in [volume/volume] units).

Solution

Let us denote as x liters a volume of the 12% acid solution to be used in the mixture, and

as y liters a volume of the 32% acid solution to be used in the mixture.

Since x liters of the 12% acid solution are mixed with y liters of the 32% acid solution, the total volume of the mixture is x+%2B+y liters.

According to the problem condition, this volume should be equal to 8 liters. This gives us the first equation

x+%2B+y+=+8.

Answer 2

Answer it was B for me

Step-by-step explanation:

Good luck