A chemist prepared a solution by adding 80 mL of ethanol (C2H5OH) (density p = 0.8 g/mL) to 256 g of water. Calculate the molar concentration and titre of the resulting solution with p = 0.97 g/mL).
Answers
Answer:
The mole fraction of solute and molality are 0.385 and 13.59 respectively
Mole fraction of solvent and molility are 0.316 and 13.59 respectively
Explanation:
The mole fraction of solute and molality are 0.385 and 13.59 respectively
Mole fraction of solvent and molality are 0.615 and 13.59 respectively
Number of moles of methanol = 30×0.8/32
=0.75
Number of moles of ethanol = 60×0.92/46
= 1.2
Mole fraction of
solute methanol = 0.75/0.75+1.2
=0.385
Mole fraction of
solvent ethanol = 1 − 0.385
= 0.615
Molality of solution = 0.75×1000/1.2×46
=13.59cm
Volume of the
solution = 30×0.8+60×0.92/0.88
=90 cm³
The molarity of solution = 0.75×1000/90
= 8.33 M