Question

A chemist wishes to prepare 6.023 *1023 molecules of Sulphur dioxide, no of gram atoms of Oxygen required is

Answer 1

Hello mate here is your answer ✌️

6.022*10^24 molecules of SO2 is approximately 10 mols of SO2.

The molar mass of sulfur is 32g/mol and there is 1 mol of sulfur in each mol of SO2.

Therefore, the chemist needs 10 mols of sulfure.

10 mol S * (32g / 1 mol) = 320g sulfur

Hope it helps ^_^

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Answer 2

Answer:

10 moles of sulphur

Explanation:

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