a child drops a ball from a height of 10 m. assume that it's velocity increase uniformly at the rate of 10m/so. find (a)the velocity with which the ball strikes the ground? (b) the time taken by the ball to reach the ground?
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height(h)=10 m
acceleration due to gravity(g)=10 m/s2
As the child drops the vall meaning free fall,initial velocity(u)=0 m/s
(a)Using the formula v2=u2+2gh,
v2=02+2*10*10
v2=200
v=under root 200=14.1421m/s
(b)Using the formula v=u+at
14.14=0+10*t
14.14=10t
14.14/10=t
t=1.414 seconds
acceleration due to gravity(g)=10 m/s2
As the child drops the vall meaning free fall,initial velocity(u)=0 m/s
(a)Using the formula v2=u2+2gh,
v2=02+2*10*10
v2=200
v=under root 200=14.1421m/s
(b)Using the formula v=u+at
14.14=0+10*t
14.14=10t
14.14/10=t
t=1.414 seconds
Answered by
17
ANSWER
Acceleration(a) = 10 m/s²
Initial Velocity(u) = 0 m/s
Final velocity be 'v' m/s
g = 10 m/s²
Now Using equation of motion:
v² + u² = 2gh
v = √2gh
= √200
= 10√2 m s⁻¹
Now, Let the time be 't' sec.
.
Equation of motion:
h = ut + 1/2gt²
h = 1/2gt²
t = √(2h/g)
t = √2 sec
∴ Velocity = 10√2 m s⁻¹
∴ Time = √2 second
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