A child drops a coin from the top of a building which is 50 M high calculate the velocity of the coin when it falls through 20 m distance and the velocity with which the choir strikes the ground take ji is equal to 10 metre per second square
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Given u=0
S=20m/s
A=10m/s^2
Applying 3rd equation i.e v^2=u^+2as,we get
V^2=0+(2*10*20)
######V=20m/s#######
Again velocity after covering 50 metre we put value of S= 50m
We get,,,,.... V^2=0+(2*10*50) =
#####10 under root 10
Note all quantities are in metre
S=20m/s
A=10m/s^2
Applying 3rd equation i.e v^2=u^+2as,we get
V^2=0+(2*10*20)
######V=20m/s#######
Again velocity after covering 50 metre we put value of S= 50m
We get,,,,.... V^2=0+(2*10*50) =
#####10 under root 10
Note all quantities are in metre
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