a child drops a coin from the top of a building which is 50 m high.calculate 1) the velocity of the coin when it falls through 20m distance and 2) the velocity with which the coin strikes ground
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Given u=0
S=20m/s
A=10m/s^2
Applying 3rd equation i.e v^2=u^+2as,we get
V^2=0+(2*10*20)
######V=20m/s#######
Again velocity after covering 50 metre we put value of S= 50m
We get,,,,.... V^2=0+(2*10*50) =
#####10 under root 10
S=20m/s
A=10m/s^2
Applying 3rd equation i.e v^2=u^+2as,we get
V^2=0+(2*10*20)
######V=20m/s#######
Again velocity after covering 50 metre we put value of S= 50m
We get,,,,.... V^2=0+(2*10*50) =
#####10 under root 10
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