If a^2-b^2= 21 and a^2+b^2=29, then what's ab?
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a²-b²=21
a²+b²=29
a²+b²+a²-b²=21+29
2a²=50
a²=25
a=√25
a=±5
a²-b²=21
25-b²=21
b²=4
b=±5
a²+b²=(a+b)²-2ab
29=±7²-2ab
29=49-2ab
ab=10
so,ab =10
hope helped
a²+b²=29
a²+b²+a²-b²=21+29
2a²=50
a²=25
a=√25
a=±5
a²-b²=21
25-b²=21
b²=4
b=±5
a²+b²=(a+b)²-2ab
29=±7²-2ab
29=49-2ab
ab=10
so,ab =10
hope helped
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