Question

A child drops
drops a stone of
1 kg
from the top of a tower. Find its kinetic energy
at sec after
it starts falling=(2 = 10m/s^2)​

Answer 1

Answer:

Mass of the stone = 1 kg.

Initial velocity of the stone = u = 0.

Acceleration = 10 m/s²

Time = 5 seconds

Finding final velocity of the stone with the help of the relation => v = u+at

v = 0 + 10×5

v = 50 m/s

Finding the kinetic energy of the stone at its instant speed :

Kinetic Energy = ½ mv²

= ½ × 1 × 50² = 1250 J

The required kinetic energy possessed by the stone at its instant speed is 1250 J.