Question

a child game has 8 triangle of which three are blue and rest are red and ten squares of which six are blue and rest are red. one piece is lost at Random find the probability of that is (a) a square (b) a triangle of red colour.

Answer 1

Answer:

Step-by-step explanation:

Here is your ans in these two pics.. Hope they will help you ❤

Answer 2

Answer:

Probability of getting square =$\frac{5}{9}$

Probability of getting a red triangle =$\frac{5}{18}$

Step-by-step explanation:

A child game has 8 triangle of which three are blue and rest are red

So, blue triangle = 3

Red triangle = 8-3 = 5

Ten squares of which six are blue and rest are red.

So, blue square = 6

Red square= 10-6 = 4

So, total number of pieces = 8 triangles +10 squares = 18

Now probability of getting square =$\frac{\text{Number of square}}{\text{total number of pieces}}$

                                                       =$\frac{10}{18}$

                                                       =$\frac{5}{9}$

Probability of getting a red triangle =$\frac{\text{Number of Red triangle}}{\text{total number of pieces}}$

                                                       =$\frac{5}{18}$

Hence Probability of getting square =$\frac{5}{9}$

Probability of getting a red triangle =$\frac{5}{18}$