A child in a boat throws a packet of mass 5 kg out horizontally with a speed of
10 m/s. Calculate the velocity of the boat immediately after, assuming initially it
was at rest. The mass of the child is 30 kg and mass of boat is 60 kg. Ignore
resistance of water.
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Momentum is conserved
m1v1 = -m2v2
v2 = -m1v1 / m2
v2 = -(5 * 10) / 90
v2 = -0.55 m/s
Velocity of boat is 55.5 cm/s in opposite direction of velocity of packet.
m1v1 = -m2v2
v2 = -m1v1 / m2
v2 = -(5 * 10) / 90
v2 = -0.55 m/s
Velocity of boat is 55.5 cm/s in opposite direction of velocity of packet.
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