Question

A child of mass 25 kg sita on a seesaw 2.0 m away from the pivot with her parent of mass 60 g on the other side of the seesaw and at distance x. find distance x for equilibrium

Answer 1

Answer:

0.834meters

Explanation:

25 kg * 2mt = 60kg * xmts

we have to find x meters

so, (25 * 2)/60 = x

50/60 = x

0.834meters = x

the parent should sit 0.83mt away from pivot to maintain equilibrium

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