Question

a child of mass 40kg is sitting at a dista

Answer 1

as we know gravitational force of attraction is Gm1*m2/r^2
and here we can see that m1=40kg
m2=50kg
r=1m
substituting these values in the formula.
F=G*50*40/1*1
F=G*200
F=6.67*10^-11*200
therefore
F=12.34*10^9N
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Answer 2

m1 = 40 kg

m2 = 50 kg

d = 1 m

$G = 6.67 \times {10}^{ - 11} Nm²/kg²$

$F = G \times \frac{m1m2}{ {d}^{2} } \\ = \frac{6.67 \times {10}^{ - 11} \times 40 \times 50 }{ {(1)}^{2} } \\ = 13340 \times {10}^{ - 11} \\ = 0.0000001334$

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