Question

find the value of p for which one root of the quadratic equation X2 - 14 x + 8 = 0 is 6 times the other

Answer 1

GOOD EVENING DEAR FRIEND

px² - 14x + 8 = 0

Let one of the roots be 'a' , then the other root is '6a'

a + 6a = 14/p

7a = 14/p

a = 2/p ---(i)

a x 6a = 8/p

6a² = 8/p

Plugging the value of a from eq (i),

6 x (2/p)² = 8/p

6 x 4/p² = 8/p

24/p = 8   (Cancelling 'p' from both the sides)

8p = 24

p = 3

So required value of 'p' is 3

HOPE THIS HELPZ

NAZ:):)

THANK U

Answer 2

x2-14x+8 eqaul zero multiply 6 and gain ans