Question

a child of weight 20 kgf is sitting at a distance of 1.5 m from the fulcrum of a see saw . what is the moment of the force of weight of child? given that 1 kgf = 10 N​

Answer 1

Answer:

Let the distance of 40 kg. from the mean position be 'x' m.

Using principle of moments,

30×2=40×x

x=1.5m.

A boy of mass 40 kg should sit at 1.5m from the middle of see-saw.

Answer 2

Answer:

300 because moment of force-force acting

*perpendicular distance of object from the force.

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