A child puts one five-rupee coin of her saving in the piggy bank on the first day. she increases her saving by one five-rupee coin daily. if the piggy bank can hold 190 coins of five rupees in all, find the number of days she can continue to put the five-rupee coins into it and find the total money she saved. write your views on the habit of saving.
Answers
Answered by
0
Answer
....
number of days divided by number of savings of 1 day
i.e.
=190/5
=38 days ANSWER.....
....
number of days divided by number of savings of 1 day
i.e.
=190/5
=38 days ANSWER.....
Answered by
7
Answer:
19 days
Step-by-step explanation:
a= 1 , d= 1 , Sn= 190 , n= ?
Sn = n/2 [ 2a + (n-1) d ]
190 = n/2 [ 2*1 + (n-1) * 1]
.: n = 19 / -20
since -20 is not possible, no. of days = n = 19 :)
amount of money = 190 * 5 = 950 Rs
you will probably have to write your views on your own cux I was searching for some views' ideas myself but ended up answering you (lol)
hope it helps :))
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