a child standing on the bridge 23 meter above the river, throws a stone in the river. find the position of the stone after 25 seconds, if the stone falls at the speed of 1 metre per second
Answers
time = 25 sec
so distance = speed × time
= 1 × 25
= 25 m
height of bridge = 23 m
so current position of stone = 23 - 25 m
= (-2) m
so position of stone is 2 m below water level
HOPE IT HELPS !!!!!!!!!!!
Concept:
This question requires the knowledge of Kinematics.
We need to know that
Distance = speed × time
Given:
The height of the bridge on which the child is standing is 23m.
Time after which we need to find the distance= 25 s
The speed with which the stone travels = 1 m/s
To find:
We need to find the position of the stone after 25 s
Solution:
We know that
distance = speed × time
where,
Speed, v = 1 m/s
Time, t = 25 s
Distance is s
Therefore
s = v × t
⇒s = 1 × 25
⇒s = 25 m
Therefore the position of the stone is 25 m below.
But, we know that the bridge is 23 m above the bridge.
Therefore,
The actual position of the stone (P)=height of the bridge from the river - s
⇒P = 23-25 = -2m
Therefore we can say that the position of the stone is 2 m below the river surface.