A child weighing 25kg slides down a rope hanging from a branch of a tall tree. If the force of friction acting against him is 2N, what is the child acceleration? (take g=10m/s^2)
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as Fnet = 25x10 - 2 = 248N.
so F = ma
248/25 = a
a = 9.92N
so F = ma
248/25 = a
a = 9.92N
surjeet682:
Sorry, answer is a=2m/s^2
okk
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