A chord 10cm long is drawn in a circle whose radius 5√2 find the areas of both the segment
Answers
Answered by
3
Consider the centre of circle to be O, ends of chord as A, B and their mid-point as M.
We have, radius, r = 5√2 cm and chord length, l = 10 cm.
Now you can observe, ∆OAM & ∆OBM are isosceles & right angled at M.
Here, angle AOM = angle BOM = 45°, then area of ∆ AOB = 25 cm²
and the area of sector AOB = ¼(circle area) = (12.5)π cm², since angle AOB = 90°.
Then area of segments are 50(π-2)/4 and 50(3π+2)/4.
this is your answer
We have, radius, r = 5√2 cm and chord length, l = 10 cm.
Now you can observe, ∆OAM & ∆OBM are isosceles & right angled at M.
Here, angle AOM = angle BOM = 45°, then area of ∆ AOB = 25 cm²
and the area of sector AOB = ¼(circle area) = (12.5)π cm², since angle AOB = 90°.
Then area of segments are 50(π-2)/4 and 50(3π+2)/4.
this is your answer
Anonymous:
2nd class mean 12th
ab sub clear huwa naa
aur plzzz apni dp change krna koi cartoon hi sahi pr dress nahii
hii
bii
pass
don't msg mee
please
farhanali i don't know u
Answered by
3
Answer:
Rate it and Like it and Mark it
Attachments:
Similar questions