Question

A chord 12 cm long is 8cm away from the centre of the circle.What is the length of chord which is 6cm away from the centre

Answer 1

Answer:

14cm

Step-by-step explanation:

its 2cm closer to the center

12+2=14

Answer 2

Answer:

Step-by-step explanation:Let the center of the circle be O and E the midpoint of AB. AEO and BEO are both RATs. AE = 12/2 = 6 cm and EO = 8 cm, so R the radius of the circle is [6^2+8^2]^0.5 = (36+64)^0.5 = 100^0.5 = 10 cm.

Now the chord CD is 6 cm from O. Let F be the midpoint of CD. CFO and DFO are both RATs. FO = 6 cm and CO = DO = 10 cm, so CF = DF =[10^2–6^2]^0.5 = (100–36)^0.5 = 64^0.5 = 8 cm, hence CD = 2*8 = 16 cm.