Question

a chord ab of a circle of radius 10 cm makes a right angle at the centre of the circle area of minor segment​

Answer 1

Step-by-step explanation:

⭐Question:

A chord ab of a circle of radius 10 cm makes a right angle at the centre of the circle area of minor segment.

⭐Answer:

Minor segments of the circle is formed by XYZ

The area of this segment can be given by this

difference of area formed by the sector OXYZ and tangle XOZ.

area of sector OXYZ = θ /360 ×πr2

r = 10cm (given)

θ = 90°

Substituting this values:

=》90/360 × 3.14 × (10)2

=》90/360 × 3.14/(10)2 × (10)2

=》1/4 × 314

π = 3.14

= 78.5

Thus area of sector OXYZ = 78.5 cm2 _____(1)

area of triangle XYZ = 1/2 × b × h

b = h = 10cm ( base and hight of triangle and equal to radius of the circle)

Substituting these values:

=》 1/2 × 10 × 10

=》 5×10

=》 50

Thus, area of triangle = 50 cm2 ______(2)

Required area of segments = equation (1)-equation (2)

=(78.5 - 50) cm2

Required area of segment = 28.5 cm2

Therefore, the area of the corresponding minor segment is 28.5 cm2

Answer 2

Answer:

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