Math, asked by aniketsaha19107, 6 months ago

a chord of 10cm long is drawn in a circle of radius 5✓2cm. find the area of the both of segments

Answers

Answered by harshika1217
2

In △OAB,

OA² + OB² = 50 + 50 = 100

AB² = 10² =100

i.e., OA² + OB² = AB² which satisfies the Pythagoras theorem. Therefore, θ = 90°

Area of minor segment = area of sector - Area of △AOB

= θ/360° x πr² -1/2 x OA x OB

= 90°/360° x 22/7 x 5root2 × 5root2 - 1/2 x 5root2 x5root2

= 39.29 - 25 = 14.29 cm²

Area of major segment = area of circle - area of minor segment

= πr² - 14.29 = 22/7 x 5root2 x 5root2 − 14.29

= 142.85cm²

See the figure also.

Hope it helps.

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