A chord of a circle is 10cm away from the centre.the ratio of the chord and the radius is 8:3.find the radius of the circle.
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Hlw mate!!
Chord length = 2 x sqroot(10^2 - 6^2) = 16 cm
Hope it helpful
Chord length = 2 x sqroot(10^2 - 6^2) = 16 cm
Hope it helpful
Answered by
0
ab=chord
m is the perpendicular from center
then mb =1/2ab
so mb:ob (o is centre)
=4:3
in triangle omb
ob^2 = ab^2 + om ^ 2
3x^2 = 4x^2 + 10^ 2
-1x^2 = 100
wait a minute the base cant be greater than the hypotenuse
pls check your question again
m is the perpendicular from center
then mb =1/2ab
so mb:ob (o is centre)
=4:3
in triangle omb
ob^2 = ab^2 + om ^ 2
3x^2 = 4x^2 + 10^ 2
-1x^2 = 100
wait a minute the base cant be greater than the hypotenuse
pls check your question again
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