Question

A chord of a circle is 30 cm long. its distance from the centre is 8 cm. Find the radius of the circle​

Answer 1

${\huge{\bf{\red{Evaluation-:}}}}$

$\implies$ ${\sf{2^2+4^2=x}}$

$\implies$ ${\sf{2+4^2=x}}$

$\implies$ ${\sf{6^2=x}}$

${\boxed{\bf{\green{6^2~or~20}}}}$

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Answer 2

Question : A chord of a circle is 30cm ling. It's distance from the centre is 8cm. Find the radius of the circle.

Given : PR = 30cm is the chord of the circle which is at distance 8cm from the circle.

To Find : Radius of the circle = ?

Solution :

Here, We will join OP

Now, PQ = $\large\dfrac{1}{2}$ × 30cm = 15cm.

So, we will create a triangle △OPQ

• By applying Pythagoras Theorem we have :

OP = $\large\sf\sqrt{OQ²+PQ²}$ = $\large\sf\sqrt{15²+8²cm}$ = 17

So, $\large\rm\underline\orange{17cm}$ is the radius of the circle