A chord of a circle is equal to the radius of the circle.Find the angle subtended by the chord at a
point on the minor arc.
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Step-by-step explanation:
Hi dude,,,,,
Here in the given figure,
Chord AB is equal to the radius OA of the circle
Therefore OA = AB = OB
OAB is an equilateral triangle
Angle O = A = B = 60 degree
If AOB is 60 then ADB is 30 degree.
( The angle subtended at any point of the circle is half the angle subtended at the centre )
ABCD is a CYCLIC QUADRILATERAL.
Therefore sum of opposite angle is supplementary.
Angle ACB = 180 - 30
= 150 degree
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