Question

How to do it? Please help me

Answer 1

Answer:

Step-by-step explanation:

Let angle ABO = angle BAO be z (as OB = OA )

In triangle OBC,

OB = BC

Thus, angle BOC = angle BCO = y ( Isoceles Angles)

Therefore, angle OBC = 180 - 2y ( Angle Sum Property )

And,

angle ABO + angle OBC = 180

z + 180- 2y = 180

z - 2y = 0

z = 2y

Now,

angle AOD = x = angle OAB + angle BCO ( External Angle of a triangel )

thus, x = y + z

Also z = 2y

Thus,

x = y + 2y = 3y

( Hence Proved )

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