A chord of a circle of a radius 6cm is making an angle 60° at the centre .Find the length of the chord...
Answers
Answered by
40
given,
radius of the circle=6cm
angle made by the chord at the center=60°
let the other angles in the triangle be x because the radii of the circle are equal
we know that,
sum of the angles in the triangle=180°
=>x+x+60°=180°
=>2x+60°=180°
=>2x=120°
=>x=60°
such that given triangle is equilateral triangle.
hence, in the equilateral triangle all sides are equal.
chord of the circle is 6 cm
HOPE U CAN UNDERSTAND
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radius of the circle=6cm
angle made by the chord at the center=60°
let the other angles in the triangle be x because the radii of the circle are equal
we know that,
sum of the angles in the triangle=180°
=>x+x+60°=180°
=>2x+60°=180°
=>2x=120°
=>x=60°
such that given triangle is equilateral triangle.
hence, in the equilateral triangle all sides are equal.
chord of the circle is 6 cm
HOPE U CAN UNDERSTAND
pls mark it as brainliest
Answered by
22
Hello Friend...
_____________________________
_____________________________
The answer of u r question is.....
Ans:
Given,
The radius of the circle OA=OB=6cm..
<AoB=60°
OC is the height from o upon AB and it is angle bisector....
then,
<CoB=30°
Consider Angle COB=30°
SIN 30°=BC/OB...
BC=6/2
=2....
BUT LENGTH OF THE CHORD AB=2BC..
=2×3=6CM
THERFORE ,
LENGTH OF THE CHORD =6CM
____________________________
____________________________
Thank you....⭐️⭐️⭐️
_____________________________
_____________________________
The answer of u r question is.....
Ans:
Given,
The radius of the circle OA=OB=6cm..
<AoB=60°
OC is the height from o upon AB and it is angle bisector....
then,
<CoB=30°
Consider Angle COB=30°
SIN 30°=BC/OB...
BC=6/2
=2....
BUT LENGTH OF THE CHORD AB=2BC..
=2×3=6CM
THERFORE ,
LENGTH OF THE CHORD =6CM
____________________________
____________________________
Thank you....⭐️⭐️⭐️
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