Math, asked by Pavan865, 1 year ago

A chord of a circle of a radius 6cm is making an angle 60° at the centre .Find the length of the chord...

Answers

Answered by wwevikash
40
given,

radius of the circle=6cm

angle made by the chord at the center=60°

let the other angles in the triangle be x because the radii of the circle are equal

we know that,

sum of the angles in the triangle=180°

=>x+x+60°=180°

=>2x+60°=180°

=>2x=120°

=>x=60°

such that given triangle is equilateral triangle.

hence, in the equilateral triangle all sides are equal.

chord of the circle is 6 cm

HOPE U CAN UNDERSTAND

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Answered by Anonymous
22
Hello Friend...

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The answer of u r question is.....

Ans:

Given,

The radius of the circle OA=OB=6cm..

<AoB=60°

OC is the height from o upon AB and it is angle bisector....

then,

<CoB=30°

Consider Angle COB=30°

SIN 30°=BC/OB...

BC=6/2

=2....

BUT LENGTH OF THE CHORD AB=2BC..

=2×3=6CM

THERFORE ,

LENGTH OF THE CHORD =6CM

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