Question

A chord of a circle of radius 10 cm subtends a right angle at its centre find the corresponding minor segment and major sector

Answer 1

Answer:

R=10 cm

∅=90°

Area of minor segment=πr^2∅/360-r^2*sin∅/2

22/7*10*10*90*1/360-10*10*sin90/2

2200/7*1/4-100*1/2

550/7-50

550-350/7

200/7 sq cm

Angle of major sector=360-90=270°

Area of major sector = πr^2∅/360

22/7*10*10*270*1/360-

2200/7*3/4

550*3/7

1650/7 sq cm