Question

a chord of a circle of radius 10 cm subtends a right angle at the centre find the area of the corresponding minor segment and major segment​

Answer 1

r=10cm tita = 90degree

area if triangle OAB =1/2×AO×BO

1/2 ×10×10 = 50cmsquare

area of the sector (O-A×B) =tita/360×πrsquare

90/360×3.14×10×10

=78.5cmsquare

area of minor segment =A(O-AxB) -A(triangleAOB)

78.5-50=28/5cmsquare

area if minor segment =28.5

area if major sector =area of circle-area of minor sector

=314 -78.5

=235.5cmsquare

area of major sector =235.5cmsquare