A chord of a circle of radius 14cm subtends an angle of 60° at the centre . Find the area of 1) minor segment 2) major segment.
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10
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Step-by-step explanation:
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mansi2654:
In the formula we have sin¢/2 * cos¢/2 . But u did not apply /2 in ur answer
U simply applied sin60° and cos 60° value without dividing it by 2
tq
Pls correct it.
no because if angle like 120 is given then we cannot apply as u said ok
ok. but u can't violate the formula
Answered by
6
Answer:
Step-by-step explanation:
Area of a segment is given by :
Area = Ф/360πr²
Where Ф is the angle subtended at the center of the circle.
The major segment is the one with the largest angle.
In this case the major segment is given by :
360 - 60 = 300°
Area of the minor segment:
60/360 × 22/7 × 14² = 102.67 cm²
The area of the major segment:
300/360 × 22/7 × 14² = 513.33 cm²
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