a chord of a circle of radius 15 cm subtends a right angle at the centre . find the area of the corresponding : (1) minor segment (2)major sector.(use pei=3.14)
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Given
Radius = 15 cm
Angle subtend = 90
Length of chord = 15√2
Are of major segment = 1/2*15*15 + 90/360*3.14*15*15 + 3.14*15*15/2
=642.375 cm²
Are of minor segment = area of circle - area of major segment = 64.125 cm²
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Solution: area of minor segment
=[π theta/360°-sin theta/2]r^2
=[3.14×90°/360°-90°/2]15×15
=[3.14/4-1/2]15×15
=[3.14-2/4]15×15
=[1.14/4]225
=[0.285]225
=64.125cm^2
Area of major segment
= πr^2- area of minor segment
=3.14×15×15-64.125
=3.14×225-64.125
=706.5-64.125
=642.375cm^2
=[π theta/360°-sin theta/2]r^2
=[3.14×90°/360°-90°/2]15×15
=[3.14/4-1/2]15×15
=[3.14-2/4]15×15
=[1.14/4]225
=[0.285]225
=64.125cm^2
Area of major segment
= πr^2- area of minor segment
=3.14×15×15-64.125
=3.14×225-64.125
=706.5-64.125
=642.375cm^2
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