A chord of a circle of radius 15 cm subtends an angle of 60 at the centre find the area of the corresponding minor and major segment of circle
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Answer:
minor segment's area is 20.38
major segment's area is 686.47
Step-by-step explanation:
a chord of a circle which subtends 60° at the center must form and equilateral triangle with the radii
so the length of the chord is 15 area of minor =
(area sector) - (area of triangle)
= {60°/360°}×π15² -( (√3)/4)15²
=(225/6)π-(√3/4)225
= 20.3818
area of major
= area of the circle - area of the minor
= 225π - 20.38
=706.85 - 20.38
= 686.477
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