A chord of a circle, of radius 15 cm, subtends an angle of 60 at the centre of the circle. Find the area of major and minor segments (take = 3.14, 3 = 1.73)
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area of segment=area of sector - ar of triangle
atq-
r=15cm
theta=60
so area of minor segment=3.14×15^2×1/6-1/2sin60×15^2
area of major segment=3.14×15^2-ar of minor segment
atq-
r=15cm
theta=60
so area of minor segment=3.14×15^2×1/6-1/2sin60×15^2
area of major segment=3.14×15^2-ar of minor segment
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