a chord of a circle of radius 21 cm substends an angle of 120° at the centre find the area of corresponding segment of the circle (use π=22/7)
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Area of sector ABDC = pie r^2/360 × 120
= pie r^2/3
= 22 × 21 × 21/ 3× 7
= 22 × 21 × 21/21
= 462
Area of ABC = 1/2 × 21 × 21 × sin120
= 1/2 × 21× 21 × sin(180-60)
= 1/2× 21× 21 × sin60
=1/2 × 21× 21 × √3/2
= 441√3/4
= 187.425
Are a of minor segment = 462 -187.425 = 274.575 cm^2
= pie r^2/3
= 22 × 21 × 21/ 3× 7
= 22 × 21 × 21/21
= 462
Area of ABC = 1/2 × 21 × 21 × sin120
= 1/2 × 21× 21 × sin(180-60)
= 1/2× 21× 21 × sin60
=1/2 × 21× 21 × √3/2
= 441√3/4
= 187.425
Are a of minor segment = 462 -187.425 = 274.575 cm^2
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