A chord of a circle of radius 21cm subtends an angle of 120 degree at the centre. Find the corresponding segment of the circle. Use pie= 3.14 and root 3 = 1.73
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area of segment of the circle is 271.2675 cm²
area of segment = 1/2 (θ- sinθ)r² [ where θ in radian ]
here given, θ = 120° = 120 × π/180 = 2π/3 rad
r = 21 cm
so, area of segment = 1/2 × {2π/3 - sin(2π/3)}(21)²
= 1/2 × 2π/3 × 21 × 21 - 1/2 × √3/2 × 21 × 21
= 22/21 × 21 × 21 - √3/4 × 441
= 22 × 21 - 1.73 × 441/4
= 462 - 190.7325
= 271.2675 cm²
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