Question

A chord of a circle of radius 6 cm, subtends an angle 60° with the center A then the area

of corresponding segment of the circle is

(A) 3.27 cm2 (B) 6 cm2 (C) 6.8 cm2 (D) None of these

​

Answer 1

Answer:

Area of minor segment =

2

36

[

180

60×3.14

−

2

3

]

= 3.27 cm

2

Step-by-step explanation:

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Answer 2

Answer:

Option A

Radius, r = 6 cm

Central angle, x = 60°

We know Area of corresponding segment =

$\frac{ {r}^{2} }{2} ( \frac{\pi \: x}{180} - sinx) \\ = \frac{6 \times 6}{2} ( \frac{22}{7} \times \frac{60}{180} - sin60) \\ = 18( \frac{22}{21} - \frac{ \sqrt{3} }{2} ) \\ = 18(1.0476 - 0.866) \\ = 3.2688 \\ =3.27 \: approx$